Okay, hereās a thing I like about Rust: Returning things as Option and error handling. (Or the more complex Result, but itās easier to explain with Option.)
fn mydiv(num: f64, denom: f64) -> Option<f64> {
// (Letās ignore precision issues for a second.)
if denom == 0.0 {
return None;
} else {
return Some(num / denom);
}
}
fn main() {
// Explicit, verbose version:
let num: f64 = 123.0;
let denom: f64 = 456.0;
let wrapped_res = mydiv(num, denom);
if wrapped_res.is_some() {
println!("Unwrapped result: {}", wrapped_res.unwrap());
}
// Shorter version using "if let":
if let Some(res) = mydiv(123.0, 456.0) {
println!("Hereās a result: {}", res);
}
if let Some(res) = mydiv(123.0, 0.0) {
println!("Huh, we divided by zero? This never happens. {}", res);
}
}
You canāt divide by zero, so the function returns an āerrorā in that case. (Option isnāt really used for errors, IIUC, but the basic idea is the same for Result.)
Option is an enum. It can have the value Some or None. In the case of Some, you can attach additional data to the enum. In this case, we are attaching a floating point value.
The caller then has to decide: Is the value None or Some? Did the function succeed or not? If it is Some, the caller can do .unwrap() on this enum to get the inner value (the floating point value). If you do .unwrap() on a None value, the program will panic and die.
The if let version using destructuring is much shorter and, once you got used to it, actually quite nice.
Now the trick is that you must somehow handle these two cases. You must either call something like .unwrap() or do destructuring or something, otherwise you canāt access the attached value at all. As I understand it, it is impossible to just completely ignore error cases. And the compiler enforces it.
(In case of Result, the compiler would warn you if you ignore the return value entirely. So something like doing write() and then ignoring the return value would be caught as well.)
#a4qstxa